572 Subtree of Another Tree

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class Solution {
  public boolean isSubtree(TreeNode root, TreeNode subRoot) {
    if (root == null) {
      return subRoot == null;
    }
    // 判断以 root 为根的二叉树是否和 subRoot 相同
    if (isSameTree(root, subRoot)) {
      return true;
    }
    // 去左右子树中判断是否有和 subRoot 相同的子树
    return isSubtree(root.left, subRoot) || isSubtree(root.right, subRoot);
  }
  public boolean isSameTree(TreeNode p, TreeNode q) {
    // 判断一对节点是否相同
    if (p == null && q == null) {
      return true;
    }
    if (p == null || q == null) {
      return false;
    }
    if (p.val != q.val) {
      return false;
    }
    // 判断其他节点是否相同
    return isSameTree(p.left, q.left) && isSameTree(p.right, q.right);
  }
}

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